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O H M I T E T H E R M A L P R O D U C T G U I D E
09 -2 018
27501 Bella Vista Parkway | Warrenville IL, 60555 | Phone: 866-9 OHMITE | Fax: 847-574-7522 | ohmite.com | email: sales@ohmite.com
Selecting a Heat Sink
1. Thermal Resistance Basics
Tc Ts Ta Tc: device case temperature (ºC)
Ts: heat sink temperature (ºC)
Ta: ambient temperature (ºC)
Q: heat dissipated (watts)
Rtheta: thermal resistance (ºC / W)
Basic thermal resistance equation
Rtheta ca = Rtheta cs + Rtheta sa = (Tc – Ta) / Q
Solving for the heat sink thermal resistance
Rtheta sa = ((Tc – Ta) / Q) – Rtheta cs
Or solving for heatsink temperature rise over ambient
(Ts – Ta) = (Tc – Ta) – (Rtheta cs x Q)
2. Calculating the Heat Sink Requirement
Example
Q = 10 watts
Tc = 150º C max
Ta = 40º C max
Rtheta cs = 1.0º C / W
(Varies with device package and interface material, such
as thermal grease, silicone pad, Kapton, phase-change
material, etc. Contact the factory for more details.)
Therefore, the thermal resistance required will be:
Rtheta sa = ((150-40) / 10) – 1 = 10º C / W
or lower value will be acceptable
Or, calculating the heat sink temperature rise:
(Ts –Ta) = (150 – 40) / (1 x 10) = 100º C
or lower value will be acceptable (at 10 W power)
3. Selecting the Heat Sink
3a. Board Mounted Heat Sink
If it is a board (PCB) mounted heat sink, there will be
a graph for the specific heat sink.
For the natural convection curve: power dissipation
(watts) vs. heat sink temperature rise above ambient
(Ts – Ta).
For the forced-convection curve: thermal resistance
from mounting surface to ambient (Rtheta sa (ºC / W) vs.
air velocity (ft. / min.)
For the specific example, (Ts – Ta) = 95º C at 10 watts
power, so this heat sink would satisfy the thermal re-
quirement in natural convection.
If the heat sink has a clip to hold the device, then the
heat sink thermal data will be given in terms of case
temperature, not sink temperature. Therefore, in natural
convection the case temperature rise above ambient
(Tc – Ta) will be plotted vs. heat dissipation. With known
values of Tc max, Ta max, and Q (watts), one can go
right to the graph for natural convection and determine
whether the heat sink will work.
For forced convection, calculate the Rtheta from the
equation and go to the graph to determine the airspeed
requirement.
Rtheta ca = (Tc - Ta) / Q
3b. Extrusion Heat Sink
If the device has higher power dissipation and an
extrusion is needed, use this quick sizing guide to find
the approximate size (volume) of the heat sink to satisfy
the thermal requirements. Then, using the data sheet
of available Ohmite extrusions, one can select potential
shapes and lengths that will meet or exceed this volume.
Example:
If the Rtheta sa calculation requirement is 1.0º C / W,
then from the chart the heat sink volume would be: For
natural convection approximately 90 cubic inches or
greater. For 500 ft./min. airspeed approximately 15 cubic
inches or greater. 90 cubic inches could be satisfied by
9.5” length of extrusion AH13070 (6 x 1.75 x 9.5). 15 cu-
bic inches could be satisfied by 3.6” length of extrusion
AH12153 (3.6 x 1.15 x 3.6).
So, 9.5 inches of AH13070 is a starting point to select
a heat sink for natural convection. 3.6 inches of AH12153
will work for 500 ft./min. of air flow. Interpolate for other
air speeds. Other selections can be made based on
available geometry of the space and any mounting con-
siderations. However, this tool is only intended to be a
first draft for selecting an extruded heat sink. For further
thermal calculations and selection assistance contact the
Ohmite Applications Engineering Desk.
The available Ohmite extrusions are found at www/
Ohmite.com/cat/sink_ah.pdf.
Sink Temp Rise Above
Ambient in Free Air (ºC)
Thermal Resistance
Sink to Ambient (ºC/W)
Thermal Resistance vs Volume
Thermal Resistance ºC / W
10 1 0.1 0.01 0.001
10000
1000
100
10
1
0.1
Heat Sink Volume (cu. in.)
Natural
500 LFM
1000 LFM
Cold Plate
CP4
Water Flow
Rate (gpm)
3
2
1
0
Rtheta cs Rtheta sa
Interface Heat Sink
Resistance Resistance
Product Guide Thermal.indd 2 9/24/2018 9:52:23 AM